The procedure is similar to that for bacteriophages with one major difference. Where bacteriophage growth is measurable in the order of minutes, cyanophage growth curves are measured in terms of hours. The burst sizes are similar, being in the tens to hundreds.
As for bacteriophages, infection should be done at a MOI between 0.1 and 0.01. In this instance, the total infective center = the phage input because the proportion of multiplyinfected host cells is small. At higher MOI, the probability of cells infected by more than one virus would increase and the total infective centers (TIC = total number of infected cells + free viruses) become less than the phage input.
The dilution factor in going from the adsorption tube to FGT is chosen so that a reasonable number of plaques (ca. 50- 200) will form on the plates during the latent period. The dilution factor in going from the FGT (first growth tube) to SGT (second growth tube) is chosen on the basis of the expected increase in plaques at the end of the rise period so that later platings of SGT samples will also yield countable numbers. As mentioned in the bacteriophage section, it is recommended to perform a preliminary one-step experiment to estimate the possible length of the latent period and burst size. Then repeat the experiment with more frequent sampling with adjustments to the dilution factors to gain more precision. Sampling times may need to be adjusted for each phage-host system.
1. Determine total phage input (Phageinput) and total cyanobacteria input (Cyanoinput).
2. At T = 0 determine the titer of unadsorbed phages (Free PhageT=0) and total infective centers (TICT=0 = initial total infected cells).
3. During the latent period and rise, determine the titer of total infective centers (TIC = total infected cells + any phages released).
4. At the end determine the titer of total progeny (TICfinal).
Adsorbed phages = Phageinput - Free PhageT=0
Percent adsorption = Adsorbed phages/ Phageinput x 100
Average MOI = Adsorbed phages/Cyanoinput
Burst size = (TICfinal/TICT=0)